but still positive), so each positive limit has a "basin of attraction" that includes an open inteval of values for $x_0$ slightly greater than the limit (and likewise, for each negative limit, an open interval of values slightly less than the limit -- since $|x_{n+1}|=|x_n\sin x_n|\le|x_n|$, successive terms in any sequence always get closer to the origin).
>>Class 11>>Maths>>Trigonometric Functions>>Trigonometric Functions of Sum and Difference of Two angles>>Prove sinn + 1x sinn + 2 x + cos n Open in AppUpdated on 2022-09-05SolutionVerified by TopprTo prove- Proof Hence any question of Trigonometric Functions with-Was this answer helpful? 00More From ChapterLearn with Videos Practice more questions
sin(n + 1) x sin (n + 2) x + cos (n + 1) x cos (n + 2) x = cos ( ( n + 2 ) x − ( n − 1 ) x ) { ∵ cos ( A − B ) = sin A sin B + cos A cos B } ⇒ = cos ( ( n + 2 − n − 1 ) x )
Trigonometry Examples Popular Problems Trigonometry Simplify 1+sinx1-sinx Step 1Apply the distributive 2Multiply by .Step 3Rewrite using the commutative property of 4Multiply .Tap for more steps...Step to the power of .Step to the power of .Step the power rule to combine and .
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sin n 1 x sin n 1 x
